2x-7x^(1/2)+3=0

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Solution for 2x-7x^(1/2)+3=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

2*x-(7*x^(1/2))+3 = 0

2*x-7*x^(1/2)+3 = 0

t_1 = x^(1/2)

2*t_1^2-7*t_1^1+3 = 0

2*t_1^2-7*t_1+3 = 0

DELTA = (-7)^2-(2*3*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+7)/(2*2) or t_1 = (7-25^(1/2))/(2*2)

t_1 = 3 or t_1 = 1/2

t_1 = 1/2

x^(1/2)-1/2 = 0

1*x^(1/2) = 1/2 // : 1

x^(1/2) = 1/2

x^(1/2) = 1/2 // ^ 2

x = 1/4

t_1 = 3

x^(1/2)-3 = 0

1*x^(1/2) = 3 // : 1

x^(1/2) = 3

x^(1/2) = 3 // ^ 2

x = 9

x in { 1/4, 9 }

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